Three forces acting on a body are shown in the figure. To have the resultant force only along the y-direction, the magnitude of the minimum additional force needed is

Question

<img class="img-fluid question-image" alt="image" src="https://cdn.tardigrade.in/img/question/physics/e363ee941b1cd49b0831a3804b0751ac-.jpeg" /> Three forces acting on a body are shown in the figure. To have the resultant force only along the y-direction, the magnitude of the minimum additional force needed is (A) (√3/4)N (B) √3N (C) 0.5 N (D) 1.5 N

Tardigrade Admin · Accepted Answer

<img class="img-fluid question-image" alt="image" src="https://cdn.tardigrade.in/img/question/physics/bb5269f484cb5652bac060c2a21b2e68-.jpeg" /> Taking x-components, the total should be zero. 1× cos 60°+ 2 cos 60° + x-4 cos 60° = 0 ∴ x= 0.5 N

Q.
Three forces acting on a body are shown in the figure. To have the resultant force only along the y-direction, the magnitude of the minimum additional force needed is

$\frac{3}{4} N$

$3 N$

$0.5 N$

$1.5 N$

Taking x-components, the total should be zero.
$1 \times cos 6 0^{\circ} + 2 cos 6 0^{\circ} + x - 4 cos 6 0^{\circ} = 0$
$∴ x = 0.5 N$

Q. Three forces acting on a body are shown in the figure. To have the resultant force only along the y-direction, the magnitude of the minimum additional force needed is

43​​N

3​N

0.5N

1.5N