Image of an object approaching a convex mirror of radius of curvature 20 m along its optical axis is observed to move from (25/3) m to (50/7) m in 30 seconds. What is the speed of the object in km per hour?

Question

Image of an object approaching a convex mirror of radius of curvature 20 m along its optical axis is observed to move from (25/3) m to (50/7) m in 30 seconds. What is the speed of the object in km per hour? (A)  (B)  (C)  (D)

Tardigrade Admin · Accepted Answer

For v1=(50/7) m , u 1=-25 m v 2=(25/3) m , u 2=-50 m Speed of object =(25/30) × (18/5)=3 kmph

Q. Image of an object approaching a convex mirror of radius of curvature $20 m$ along its optical axis is observed to move from $\frac{25}{3} m$ to $\frac{50}{7} m$ in $30$ seconds. What is the speed of the object in $km$ per hour?

For $v_{1} = \frac{50}{7} m,$
$u_{1} = - 25 m$
$v_{2} = \frac{25}{3} m,$
$u_{2} = - 50 m$
Speed of object $= \frac{25}{30} \times \frac{18}{5} = 3 km p h$

Q. Image of an object approaching a convex mirror of radius of curvature 20m along its optical axis is observed to move from 325​m to 750​m in 30 seconds. What is the speed of the object in km per hour?

For v1​=750​m, u1​=−25m v2​=325​m, u2​=−50m Speed of object =3025​×518​=3kmph

Q. Image of an object approaching a convex mirror of radius of curvature $20 m$ along its optical axis is observed to move from $\frac{25}{3} m$ to $\frac{50}{7} m$ in $30$ seconds. What is the speed of the object in $km$ per hour?

For $v_{1} = \frac{50}{7} m,$
$u_{1} = - 25 m$
$v_{2} = \frac{25}{3} m,$
$u_{2} = - 50 m$
Speed of object $= \frac{25}{30} \times \frac{18}{5} = 3 km p h$