Tardigrade
Tardigrade - CET NEET JEE Exam App
Exams
Login
Signup
Tardigrade
Question
Mathematics
If z is a complex number such that |z| ge 2, then the minimum value of |z+(1/2)|
Q. If z is a complex number such that
∣
z
∣
≥
2
,
then the minimum value of
∣
∣
z
+
2
1
∣
∣
2050
264
JEE Main
JEE Main 2014
Complex Numbers and Quadratic Equations
Report Error
A
is strictly greater than
2
5
17%
B
is strictly greater than
2
3
but less 5 than
2
5
63%
C
is equal to
2
5
17%
D
lies in the interval (1, 2)
4%
Solution:
∣
∣
z
+
2
1
∣
∣
So,
∣
z
∣
∣
−
2
1
∣
∣
≤
∣
∣
z
+
2
1
∣
∣
⇒
∣
∣
z
+
2
1
∣
∣
≥
∣
∣
2
−
2
1
∣
∣
⇒
∣
∣
z
m
i
n
.
=
2
3
∣
∣