Tardigrade
Tardigrade - CET NEET JEE Exam App
Exams
Login
Signup
Tardigrade
Question
Mathematics
If (z-α/z+α) (α∈ R) is a purely imaginary number and |z| = 2, then a value of α is :
Q. If
z
+
α
z
−
α
(
α
∈
R
)
is a purely imaginary number and
∣
z
∣
=
2
, then a value of
α
is :
4309
234
JEE Main
JEE Main 2019
Complex Numbers and Quadratic Equations
Report Error
A
1
0%
B
2
33%
C
2
56%
D
2
1
11%
Solution:
z
+
α
z
−
α
+
z
ˉ
+
α
z
ˉ
−
α
=
0
z
z
ˉ
+
z
α
−
α
z
ˉ
−
α
2
+
z
z
ˉ
−
z
α
+
z
ˉ
α
−
α
2
=
0
∣
z
∣
2
=
α
2
,
a
=
±
2