Tardigrade
Tardigrade - CET NEET JEE Exam App
Exams
Login
Signup
Tardigrade
Question
Mathematics
If z=2+i, then (z-1)( barz-5)+( barz-1)(z-5) is equal to
Q. If
z
=
2
+
i
, then
(
z
−
1
)
(
z
ˉ
−
5
)
+
(
z
ˉ
−
1
)
(
z
−
5
)
is equal to
5748
224
Complex Numbers and Quadratic Equations
Report Error
A
2
15%
B
7
20%
C
−
1
21%
D
−
4
44%
Solution:
(
z
−
1
)
(
z
ˉ
−
5
)
+
(
z
ˉ
−
1
)
(
z
−
5
)
=
2
R
e
[
(
z
−
1
)
(
z
ˉ
−
5
)
]
(
∵
z
1
z
ˉ
2
+
z
2
z
ˉ
1
=
2
R
e
(
z
1
z
ˉ
2
)
)
=
2
R
e
[
(
1
+
i
)
(
−
3
−
i
)
]
=
2
(
−
2
)
=
−
4
(Given
z
=
2
+
i
)