Q. If $z = 2 - 3 i$ , then the value of $z^{2} - 4 z + 13$ is

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A

1

12%

B

$- 1$

23%

C

0

45%

D

None of these

21%

Solution:

$z = 2 - 3 i$
$\Rightarrow z - 2 = - 3 i$
Squaring, we get
$z^{2} - 4 z + 4 = - 9$
$\Rightarrow z^{2} - 4 z + 13 = 0$