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Q. If $z=2-3i$, then the value of $z^{2}-4 z+13$ is

Complex Numbers and Quadratic Equations

Solution:

$z=2-3 i $
$\Rightarrow z-2=-3 i$
Squaring, we get
$z^{2}-4 z+4=-9 $
$\Rightarrow z^{2}-4 z+13=0$