Question

If $y(x)$ be the solution of differential equation $x\log x\frac{dy}{dx}+y=2x\log x,y(e)$ is equal to

• A. e
• B. 2
• C. 0
• D. 2 e

Answer 1

Answer: (D)

$I.F=\log x$,
$y\log x=2x(\log x-1)+c$
If $x=e$ then $y=c$ then $y(e)=2e$