Q. If $y = sec^{2} θ + cos^{2} θ, θ \neq = 0$ then

2953 269 Trigonometric Functions Report Error

A

$y = 0$

B

$y \leq 2$

C

$y \geq 2$

D

$y > 2$

Solution:

$y = \frac{1}{c o s ^{2} θ} + cos^{2} θ \geq 2$
but $θ \neq = 0, y \neq = 2 [i f a > 0, a + \frac{1}{a} \geq 2]$