Tardigrade
Tardigrade - CET NEET JEE Exam App
Exams
Login
Signup
Tardigrade
Question
Mathematics
If y = f ((5x + 1/10x2 - 3) ) and f'(x) = cos x ,then (dy/dx) =
Q. If
y
=
f
(
10
x
2
−
3
5
x
+
1
)
and
f
′
(
x
)
=
cos
x
,then
d
x
d
y
=
4127
206
Continuity and Differentiability
Report Error
A
cos
(
10
x
2
−
3
5
x
+
1
)
d
x
d
(
10
x
2
−
3
5
x
+
1
)
39%
B
10
x
2
−
3
5
x
+
1
cos
(
10
x
2
−
3
5
x
+
1
)
32%
C
cos
(
10
x
2
−
3
5
x
+
1
)
23%
D
none of these
6%
Solution:
Suppose that
t
=
10
x
2
−
3
5
x
+
1
, so
y
=
f
(
t
)
∴
d
x
d
y
=
f
′
(
t
)
.
d
x
d
t
[Since
f
′
(
x
)
=
cos
x
]
d
x
d
y
=
cos
(
10
x
2
−
3
5
x
+
1
)
d
x
d
(
10
x
2
−
3
5
x
+
1
)