Question

If $y=e^{\sqrt{x}}+e^{-\sqrt{x}}$ then $\frac{dy}{dx}$ equals -

• A. $\frac{e^{\sqrt{x}}-e^{-\sqrt{x}}}{2\sqrt{x}}$
• B. $\frac{e^{\sqrt{x}}-e^{-\sqrt{x}}}{2x}$
• C. $\frac{1}{2\sqrt{x}}\sqrt{y^2-4}$
• D. $\frac{1}{2\sqrt{x}}\sqrt{y^2+4}$

Answer 1

Answer: (A), (C)

Correct answer is (a) $\frac{e^{\sqrt{x}}-e^{-\sqrt{x}}}{2\sqrt{x}}$ Correct answer is (c) $\frac{1}{2\sqrt{x}}\sqrt{y^2-4}$