if [x y z] = (1/40) [5&10&-5 -5&-2&13 10&-4&6][5 0 5], then the value of x + y + z is

Question

if [x y z] = (1/40) [5&10&-5 -5&-2&13 10&-4&6][5 0 5], then the value of x + y + z is (A) 3 (B) 0 (C) 2 (D) 1

Tardigrade Admin · Accepted Answer

Given[x y z] = (1/40) [5&10&-5 -5&-2&13 10&-4&6][5 0 5] = (1/40) [25&+0&-25 -25&+0&+65 50&+0&+30]= (1/40)[0 40 80]= [0 1 2] ⇒ x = 0, y = 1, z = 2 ∴ x + y + z = 0 + 1 + 2 = 3

Q. if $⎣ ⎡ x y z ⎦ ⎤ = \frac{1}{40} ⎣ ⎡ 5 - 5 10 10 - 2 - 4 - 5 136 ⎦ ⎤ ⎣ ⎡ 505 ⎦ ⎤$ , then the value of $x + y + z$ is

$3$

$0$

$2$

$1$

Q. if ⎣⎡​xyz​⎦⎤​=401​⎣⎡​5−510​10−2−4​−5136​⎦⎤​⎣⎡​505​⎦⎤​, then the value of x+y+z is

3

0

2

1

Given⎣⎡​xyz​⎦⎤​=401​⎣⎡​5−510​10−2−4​−5136​⎦⎤​⎣⎡​505​⎦⎤​ =401​⎣⎡​25−2550​+0+0+0​−25+65+30​⎦⎤​=401​⎣⎡​04080​⎦⎤​=⎣⎡​012​⎦⎤​ ⇒x=0,y=1,z=2 ∴x+y+z=0+1+2=3

Q. if $⎣ ⎡ x y z ⎦ ⎤ = \frac{1}{40} ⎣ ⎡ 5 - 5 10 10 - 2 - 4 - 5 136 ⎦ ⎤ ⎣ ⎡ 505 ⎦ ⎤$ , then the value of $x + y + z$ is

$3$

$0$

$2$

$1$