Tardigrade
Tardigrade - CET NEET JEE Exam App
Exams
Login
Signup
Tardigrade
Question
Mathematics
If x2+y2=9 4 a2+9 b2=16, then maximum value of 4 a2 x2+9 b2 y2-12 a b x y is -
Q. If
x
2
+
y
2
=
9&4
a
2
+
9
b
2
=
16
, then maximum value of
4
a
2
x
2
+
9
b
2
y
2
−
12
ab
x
y
is -
482
220
Trigonometric Functions
Report Error
A
81
B
100
C
121
D
144
Solution:
Correct answer is (d) 144