If x2+y2=1, then the point P(x, y, √1-x2-y2) is at a distance of ...A ... units from the origin. Here, A refers to

Question

If x2+y2=1, then the point P(x, y, √1-x2-y2) is at a distance of ...A ... units from the origin. Here, A refers to (A) 1 (B) 2 (C) 3 (D) 4

Tardigrade Admin · Accepted Answer

The coordinates of point P are (x, y, √1-x2-y2). Then, O P =√(x-0)2+(y-0)2+(√1-x2-y2-0)2 =√x2+y2+1-x2-y2=√1=1

Q. If $x^{2} + y^{2} = 1$ , then the point $P (x, y, 1 - x^{2} - y^{2})$ is at a distance of ...A ... units from the origin. Here, A refers to