If |x2+x&x+1&x-2 2x2+3x-1&3x&3x-3 x2+2x+3&2x-1&2x-1|=ax-12, then 'a' is equal to :

Question

If |x2+x&x+1&x-2 2x2+3x-1&3x&3x-3 x2+2x+3&2x-1&2x-1|=ax-12, then 'a' is equal to : (A) 12 (B) 24 (C) - 12 (D) - 24

Tardigrade Admin · Accepted Answer

Δ=|x2+x x+1 x-2 2 x2+3 x-1 3 x 3 x-3 x2+2 x+3 2 x-1 2 x-1|=a x-12 Operating R2 arrow R2-(R1+R3) gives, Δ= |x2+x x+1 x-2 -4 0 0 x2+2 x+3 2 x-1 2 x-1| ⇒ Δ=-(-4)|x+1 x-2 2 x-1 2 x-1|=4(2 x-1) |x+1 x-2 1 1|=4(2 x-1)(x+1-x+2) =4(2 x-1)(3)=24 x-12=a x-12 (given) ⇒ a=24

Q. If ∣∣​x2+x2x2+3x−1x2+2x+3​x+13x2x−1​x−23x−32x−1​∣∣​=ax−12, then 'a' is equal to :

12

24

- 12

- 24

Q. If $∣ ∣ x^{2} + x 2 x^{2} + 3 x - 1 x^{2} + 2 x + 3 x + 1 3 x 2 x - 1 x - 2 3 x - 3 2 x - 1 ∣ ∣ = a x - 12,$ then 'a' is equal to :