Question

If $|x+2|\le 9$, then

• A. $x\in \left(-7,11\right)$
• B. $x\in \left[-11,7\right]$
• C. $x\in \left(-\infty ,-7\right)\cup \left(11,\infty \right)$
• D. $x\in \left(-\infty ,-7\right)\cup [11,\infty )$

Answer 1

Answer: (B)

Given, $|x+2|\le 9$
$\Rightarrow -9\le x+2\le 9$
$\Rightarrow -11\le x\le 7$