If x2-5 x-140 ⇒ x lie outside [α, β], then (α/β)=

Question

If x2-5 x-14>0 ⇒ x lie outside [α, β], then (α/β)= (A) (-2/7) (B) (-7/2) (C) (2/7) (D) (7/2)

Tardigrade Admin · Accepted Answer

x2-5 x-14>0 ⇒(x+2)(x-7)>0 x<-2 text or x>7 ⇒ α=-2 text or β=7 (α/β)=(-2/7)

Q. If $x^{2} - 5 x - 14 > 0 \Rightarrow x$ lie outside $[α, β]$ , then $\frac{α}{β} =$