If x1, x2 are roots of the equation x2-6 x+4=0, then find the value of ((x1-2)16+(x2-6)8/x18).

Question

If x1, x2 are roots of the equation x2-6 x+4=0, then find the value of ((x1-2)16+(x2-6)8/x18). (A)  (B)  (C)  (D)

Tardigrade Admin · Accepted Answer

Expression =(256 x18+(48/x28)/x18)=256+1=257

Q. If $x_{1}, x_{2}$ are roots of the equation $x^{2} - 6 x + 4 = 0$ , then find the value of $\frac{( x _{1} - 2 ) ^{16} + ( x _{2} - 6 ) ^{8}}{x _{1}^{8}}$ .