If x1 be the size of the magnified image and x2 the size of the diminished image in Lens Displacement Method, then the size of the object is

Question

If x1 be the size of the magnified image and x2 the size of the diminished image in Lens Displacement Method, then the size of the object is (A) √x1 x2 (B) x1 x2 (C) x12 x2 (D) x1 x2 2

Tardigrade Admin · Accepted Answer

The size of the object in accordance with the Fresnel's displacement law is given by √x1 x2.

Q. If $x_{1}$ be the size of the magnified image and $x_{2}$ the size of the diminished image in Lens Displacement Method, then the size of the object is

$x_{1} x_{2}$

$x_{1} x_{2}$

$x_{1}^{2} x_{2}$

$x_{1} x_{2}^{2}$

The size of the object in accordance with the Fresnel's displacement law is given by $x_{1} x_{2}$ .

Q. If x1​ be the size of the magnified image and x2​ the size of the diminished image in Lens Displacement Method, then the size of the object is

x1​x2​​

x1​x2​

x12​x2​

x1​x22​

The size of the object in accordance with the Fresnel's displacement law is given by x1​x2​​.

Q. If $x_{1}$ be the size of the magnified image and $x_{2}$ the size of the diminished image in Lens Displacement Method, then the size of the object is

$x_{1} x_{2}$

$x_{1} x_{2}$

$x_{1}^{2} x_{2}$

$x_{1} x_{2}^{2}$

The size of the object in accordance with the Fresnel's displacement law is given by $x_{1} x_{2}$ .