If x1 and x2 are the points of local minima and x3 is the point of local maxima of the function f(x)=x2-4 x+(25/4)-3|x-2|, then

Question

If x1 and x2 are the points of local minima and x3 is the point of local maxima of the function f(x)=x2-4 x+(25/4)-3|x-2|, then (A) x1+x2+x3=4 (B) x 1+ x 2+ x 3=6 (C) f(x1)+f(x2)+f(x3)=(17/4) (D)  f ( x 1)+ f ( x 2)+ f ( x 3)=(9/4)

Tardigrade Admin · Accepted Answer

Correct answer is (b) x 1+ x 2+ x 3=6Correct answer is (d) f ( x 1)+ f ( x 2)+ f ( x 3)=(9/4)

Q. If $x_{1}$ and $x_{2}$ are the points of local minima and $x_{3}$ is the point of local maxima of the function $f (x) = x^{2} - 4 x + \frac{25}{4} - 3∣ x - 2∣$ , then

$x_{1} + x_{2} + x_{3} = 4$

$x_{1} + x_{2} + x_{3} = 6$

$f (x_{1}) + f (x_{2}) + f (x_{3}) = \frac{17}{4}$

$f (x_{1}) + f (x_{2}) + f (x_{3}) = \frac{9}{4}$

Correct answer is (b) $x_{1} + x_{2} + x_{3} = 6$ Correct answer is (d) $f (x_{1}) + f (x_{2}) + f (x_{3}) = \frac{9}{4}$

Q. If x1​ and x2​ are the points of local minima and x3​ is the point of local maxima of the function f(x)=x2−4x+425​−3∣x−2∣, then

x1​+x2​+x3​=4

x1​+x2​+x3​=6

f(x1​)+f(x2​)+f(x3​)=417​

f(x1​)+f(x2​)+f(x3​)=49​