Question

If wave equation is $y=0.08\sin \frac{2\pi }{\lambda }(200t-x)$ then the velocity of the wave will be

• A. $400\sqrt{2}m/s$
• B. $200\sqrt{2}m/s$
• C. $400m/s$
• D. $200m/s$

Answer 1

Answer: (D)

Given :
$y=0.08\sin \frac{2\pi }{\lambda }(200t-x)$ ...(1)
Standard equation is given by
$y=a\sin \frac{2\pi }{\lambda }(vt-x)$ ...(2)
On comparing eqs $(1)$ and $(2)$
$v=200m/s$