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Tardigrade
Question
Physics
If voltage V=( 100± 5 ) volt and current 1=( 10± 0.2 )A, the percentage error in resistance R is
Q. If voltage
V
=
(
100
±
5
)
volt and current
1
=
(
10
±
0.2
)
A
,
the percentage error in resistance R is
1162
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A
5.2%
B
25%
C
7%
D
10%
Solution:
Given voltage
V
=
(
100
±
5
)
volt, Current
I
=
(
10
±
0.2
)
A
From Ohms law
V
=
I
R
∴
Resistance
R
=
I
V
Maximum percentage error in resistance
(
R
Δ
R
×
100
)
=
(
V
Δ
V
×
100
)
+
(
I
Δ
I
×
100
)
=
(
100
5
×
100
)
+
(
10
0.2
×
100
)
=
5
+
2
=
7