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Physics
If voltage V=( 100± 5 ) volt and current 1=( 10± 0.2 )A, the percentage error in resistance R is
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Q. If voltage $ V=\left( 100\pm 5 \right) $ volt and current $ 1=\left( 10\pm 0.2 \right)A, $ the percentage error in resistance R is
CMC Medical
CMC Medical 2008
A
5.2%
B
25%
C
7%
D
10%
Solution:
Given voltage $ V=\left( 100\pm 5 \right) $ volt, Current $ I~=\left( 10\text{ }\pm 0.2 \right)\,A $ From Ohms law $ V=IR $ $ \therefore $ Resistance $ R=\frac{V}{I} $ Maximum percentage error in resistance $ \left( \frac{\Delta R}{R}\times 100 \right)=\left( \frac{\Delta V}{V}\times 100 \right)+\left( \frac{\Delta I}{I}\times 100 \right) $ $ =\left( \frac{5}{100}\times 100 \right)+\left( \frac{0.2}{10}\times 100 \right) $ $ =5+2=7% $