If van't Hoff factor for KCl is 1.8 . What is the boiling point of 0.75m solution of KCl in water Kb=0.5° Ckg/mol ?

Question

If van't Hoff factor for KCl is 1.8 . What is the boiling point of 0.75m solution of KCl in water Kb=0.5° Ckg/mol ? (A) 0.67° C (B) 100.67K (C) 99.37° C (D) 373.67K

Tardigrade Admin · Accepted Answer

ΔTb=i× Kb× m =1.78× (.0.5.)× (.0.75.) ΔTb=0.67° C Tb=Tb° +ΔTb =100° C+0.67° C Tb=100.67° C

Q. If van't Hoff factor for $K Cl$ is $1.8$ . What is the boiling point of $0.75 m$ solution of $K Cl$ in water $K_{b} = 0. 5^{\circ} C k g / m o l$ ?

$0.6 7^{\circ} C$

$100.67 K$

$99.3 7^{\circ} C$

$373.67 K$

$Δ T_{b} = i \times K_{b} \times m$
$= 1.78 \times (0.5) \times (0.75)$
$Δ T_{b} = 0.6 7^{\circ} C$
$T_{b} = T_{b}^{\circ} + Δ T_{b}$
$= 10 0^{\circ} C + 0.6 7^{\circ} C$
$T_{b} = 100.6 7^{\circ} C$

Q. If van't Hoff factor for KCl is 1.8 . What is the boiling point of 0.75m solution of KCl in water Kb​=0.5∘Ckg/mol ?

0.67∘C

100.67K

99.37∘C

373.67K