If uniform electric field vecE=E0 hati+2 E0 hatj, where E0 is a constant, exists in a region of space and at (0,0) the electric potential V is zero, then the potential at (x0, 0) will be:

Question

If uniform electric field vecE=E0 hati+2 E0 hatj, where E0 is a constant, exists in a region of space and at (0,0) the electric potential V is zero, then the potential at (x0, 0) will be: (A) zero (B) -E0 x0 (C) -2 E0 x0 (D) -√5 E0 x0

Tardigrade Admin · Accepted Answer

A=(0,0), B=(x0, 0) =∫ limitsAB vecE . d r=VA-VB=0-VB E0 x0= -VB VB=-E0 x0

Q. If uniform electric field $E = E_{0} \hat{i} + 2 E_{0} \hat{j}$ , where $E_{0}$ is a constant, exists in a region of space and at $(0, 0)$ the electric potential $V$ is zero, then the potential at $(x_{0}, 0)$ will be:

zero

$- E_{0} x_{0}$

$- 2 E_{0} x_{0}$

$- 5 E_{0} x_{0}$

$A = (0, 0), B = (x_{0}, 0)$
$= A \int B E . d r = V_{A} - V_{B} = 0 - V_{B}$
$E_{0} x_{0} = - V_{B}$
$V_{B} = - E_{0} x_{0}$

Q. If uniform electric field E=E0​i^+2E0​j^​, where E0​ is a constant, exists in a region of space and at (0,0) the electric potential V is zero, then the potential at (x0​,0) will be:

zero

−E0​x0​

−2E0​x0​

−5​E0​x0​

A=(0,0),B=(x0​,0) =A∫B​E.dr=VA​−VB​=0−VB​ E0​x0​=−VB​ VB​=−E0​x0​

Q. If uniform electric field $E = E_{0} \hat{i} + 2 E_{0} \hat{j}$ , where $E_{0}$ is a constant, exists in a region of space and at $(0, 0)$ the electric potential $V$ is zero, then the potential at $(x_{0}, 0)$ will be:

$- E_{0} x_{0}$

$- 2 E_{0} x_{0}$

$- 5 E_{0} x_{0}$

$A = (0, 0), B = (x_{0}, 0)$
$= A \int B E . d r = V_{A} - V_{B} = 0 - V_{B}$
$E_{0} x_{0} = - V_{B}$
$V_{B} = - E_{0} x_{0}$