If two squares are chosen at random on a chess board, the probability that they have a side in common is

Question

If two squares are chosen at random on a chess board, the probability that they have a side in common is (A) (1/9) (B) (2/7) (C) (1/18) (D) (2/9)

Tardigrade Admin · Accepted Answer

Two squares out of 64 can be selected in

^{64} C_{2} = \frac{64 \times 63}{2} = 32 \times 63

ways
The number of ways of selecting those pairs which have a side in common

= (\frac{1}{2})

(4 \times 2 + 24 \times 3 + 36 \times 4) = 112

[Since each of the corner squares has two neighbours each of 24 squares in border other than corner ones has three neighbours and each of the remaining 36 squares have four neighours and in this computation, each pair of squares has been counted twice].
Hence required probability

= \frac{112}{32 \times 63} = \frac{1}{18}

Q. If two squares are chosen at random on a chess board, the probability that they have a side in common is

$\frac{1}{9}$

$\frac{2}{7}$

$\frac{1}{18}$

$\frac{2}{9}$

Q. If two squares are chosen at random on a chess board, the probability that they have a side in common is

91​

72​

181​

92​

$\frac{1}{9}$

$\frac{2}{7}$

$\frac{1}{18}$

$\frac{2}{9}$