If two springs A and B with spring constants 2k and k, are stretched separately by same suspended weight, then the ratio between the work done in stretching A and B is

Question

If two springs A and B with spring constants 2k and k, are stretched separately by same suspended weight, then the ratio between the work done in stretching A and B is (A) 1: 2 (B) 1: 4 (C) 1: 3 (D) 4: 1

Tardigrade Admin · Accepted Answer

mg=2 KxA mg=KxB (xA/xB)=(1/2) W=Fx So, (WA/WB)=(FxA/FxB)=(1/2)

Q. If two springs A and B with spring constants 2k and k, are stretched separately by same suspended weight, then the ratio between the work done in stretching A and B is

1 : 2

1 : 4

1 : 3

4 : 1

2 : 1

$m g = 2 K x_{A}$ $m g = K x_{B}$
$\frac{x _{A}}{x _{B}} = \frac{1}{2}$
$W = F x$
So, $\frac{W _{A}}{W _{B}} = \frac{F x _{A}}{F x _{B}} = \frac{1}{2}$