If two numbers are in the ratio (1/15): (1/20), then by what percentage is the second number less than the first? The following steps are involved in solving the above problem. Arrange them in sequential order. (A) Difference between the two numbers is 4 x-3 x=x. (B) Given that the ratio of two numbers =(1/15): (1/20)=20: 15=4: 3. Let the numbers be 4 x and 3 x. (C) The percentage by which the second number is less than the first number =(x/4 x) × 100 %=25 %. (D) i.e., the second number is x less than the first number.

Question

If two numbers are in the ratio (1/15): (1/20), then by what percentage is the second number less than the first? The following steps are involved in solving the above problem. Arrange them in sequential order. (A) Difference between the two numbers is 4 x-3 x=x. (B) Given that the ratio of two numbers =(1/15): (1/20)=20: 15=4: 3. Let the numbers be 4 x and 3 x. (C) The percentage by which the second number is less than the first number =(x/4 x) × 100 %=25 %. (D) i.e., the second number is x less than the first number. (A) BADC (B) BDAC (C) DBAC (D) ABDC

Tardigrade Admin · Accepted Answer

(B),(A),(D) and (C) is the required sequential order.

$B A D C$

$B D A C$

$D B A C$

$A B D C$

$(B), (A), (D)$ and $(C)$ is the required sequential order.