Tardigrade
Tardigrade - CET NEET JEE Exam App
Exams
Login
Signup
Tardigrade
Question
Mathematics
If θ ∈[0,5 π] and r ∈ R such that 2 sin θ= r 4-2 r 2+3 then the maximum number of values of the pair ( r , θ) is
Q. If
θ
∈
[
0
,
5
π
]
and
r
∈
R
such that
2
sin
θ
=
r
4
−
2
r
2
+
3
then the maximum number of values of the pair
(
r
,
θ
)
is _______
1490
206
Trigonometric Functions
Report Error
Answer:
6
Solution:
2
sin
θ
=
r
4
−
2
r
2
+
3
⇒
2
sin
θ
=
(
r
2
−
1
)
2
+
2
This is possible only when
sin
θ
=
1
and
r
2
=
1
or
r
=
±
1
.
So,
θ
=
π
/2
,
5
π
/2
,
9
π
/2
∴
Number of values of the pair
(
r
,
θ
)
=
6