If the work function of the photoelectric surface is 3.3 eV, then the value of threshold frequency is

Question

If the work function of the photoelectric surface is 3.3 eV, then the value of threshold frequency is (A)  8 × 10 14 Hz (B)  5 × 10 16 Hz (C)  4 × 10 11 Hz (D)  8 × 10 10 Hz

Tardigrade Admin · Accepted Answer

E = h v 3.3 × 1.6 × 10 - 19 = 6.6 × 10 - 34 × v ⇒ v = ( 3.3 × 1.6 × 10 - 19 / 6.6 × 10 - 34 ) = 0.8 × 10 15 = 8 Ã 1014 Hz

Q. If the work function of the photoelectric surface is 3.3 eV, then the value of threshold frequency is

$8 \times 1 0^{14}$ Hz

$5 \times 1 0^{16}$ Hz

$4 \times 1 0^{11}$ Hz

$8 \times 1 0^{10}$ Hz

E = h v
$3.3 \times 1.6 \times 1 0^{- 19} = 6.6 \times 1 0^{- 34} \times v$
$\Rightarrow v = \frac{3.3 \times 1.6 \times 1 0 ^{- 19}}{6.6 \times 1 0 ^{- 34}}$
= 0.8 $\times 1 0^{15}$
$= 8 \times 1 0^{14} Hz$

Q. If the work function of the photoelectric surface is 3.3 eV, then the value of threshold frequency is

8×1014 Hz

5×1016 Hz

4×1011 Hz

8×1010 Hz

E = h v 3.3×1.6×10−19=6.6×10−34×v ⇒v=6.6×10−343.3×1.6×10−19​ = 0.8 ×1015 =8×1014Hz

$8 \times 1 0^{14}$ Hz

$5 \times 1 0^{16}$ Hz

$4 \times 1 0^{11}$ Hz

$8 \times 1 0^{10}$ Hz

E = h v
$3.3 \times 1.6 \times 1 0^{- 19} = 6.6 \times 1 0^{- 34} \times v$
$\Rightarrow v = \frac{3.3 \times 1.6 \times 1 0 ^{- 19}}{6.6 \times 1 0 ^{- 34}}$
= 0.8 $\times 1 0^{15}$
$= 8 \times 1 0^{14} Hz$