If the velocity of the revolving electron of He + in the first orbit ( n =1 ) is v, the velocity of the electron in the second orbit is :

Question

If the velocity of the revolving electron of He + in the first orbit ( n =1 ) is v, the velocity of the electron in the second orbit is : (A) v (B) 0.5 v (C) 2 v (D) 0.25 v

Tardigrade Admin · Accepted Answer

For single electron species vn propto (1/n) (v2/v1)=( n 1/ n 2)=(1/2) v2=(1/2) v1=(1/2) v=(v/2)=0.5 v

Q. If the velocity of the revolving electron of $H e^{+}$ in the first orbit $(n = 1$ ) is $v$ , the velocity of the electron in the second orbit is :

v

0.5 v

2 v

0.25 v

For single electron species $v_{n} \propto \frac{1}{n}$
$\frac{v _{2}}{v _{1}} = \frac{n _{1}}{n _{2}} = \frac{1}{2}$
$v_{2} = \frac{1}{2} v_{1} = \frac{1}{2} v = \frac{v}{2} = 0.5 v$

Q. If the velocity of the revolving electron of He+ in the first orbit (n=1 ) is v, the velocity of the electron in the second orbit is :

v

0.5 v

2 v

0.25 v

For single electron species vn​∝n1​ v1​v2​​=n2​n1​​=21​ v2​=21​v1​=21​v=2v​=0.5v

Q. If the velocity of the revolving electron of $H e^{+}$ in the first orbit $(n = 1$ ) is $v$ , the velocity of the electron in the second orbit is :

For single electron species $v_{n} \propto \frac{1}{n}$
$\frac{v _{2}}{v _{1}} = \frac{n _{1}}{n _{2}} = \frac{1}{2}$
$v_{2} = \frac{1}{2} v_{1} = \frac{1}{2} v = \frac{v}{2} = 0.5 v$