If the velocity of light in vacuum is 3×108 ms-1, the time taken (in nanosecond) to travel through a glass plate of thickness 10 cm and refractive index 1.5 is

Question

If the velocity of light in vacuum is 3×108 ms-1, the time taken (in nanosecond) to travel through a glass plate of thickness 10 cm and refractive index 1.5 is (A) 0.5 (B) 1.0 (C) 2.0 (D) 3.0

Tardigrade Admin · Accepted Answer

Given v=3 × 108 ms -1, d=10 m and μ=1.5 Here, t=(d/c / μ) t=(10 × 10-2/2 × 108) (∴ (c/μ)=(3 × 108/1.5)=2 × 108 ms -1) t=0.5 × 10-9 s

Q. If the velocity of light in vacuum is $3 \times 1 0^{8} m s^{- 1},$ the time taken (in nanosecond) to travel through a glass plate of thickness $10 c m$ and refractive index $1.5$ is

0.5

1.0

2.0

3.0

Given $v = 3 \times 1 0^{8} m s^{- 1}, d = 10 m$ and $μ = 1.5$
Here, $t = \frac{d}{c / μ}$
$t = \frac{10 \times 1 0 ^{- 2}}{2 \times 1 0 ^{8}}$
$(∴ \frac{c}{μ} = \frac{3 \times 1 0 ^{8}}{1.5} = 2 \times 1 0^{8} m s^{- 1})$
$t = 0.5 \times 1 0^{- 9} s$

Q. If the velocity of light in vacuum is 3×108ms−1, the time taken (in nanosecond) to travel through a glass plate of thickness 10cm and refractive index 1.5 is

0.5

1.0

2.0

3.0

Given v=3×108ms−1,d=10m and μ=1.5 Here, t=c/μd​ t=2×10810×10−2​ (∴μc​=1.53×108​=2×108ms−1) t=0.5×10−9s

Q. If the velocity of light in vacuum is $3 \times 1 0^{8} m s^{- 1},$ the time taken (in nanosecond) to travel through a glass plate of thickness $10 c m$ and refractive index $1.5$ is

Given $v = 3 \times 1 0^{8} m s^{- 1}, d = 10 m$ and $μ = 1.5$
Here, $t = \frac{d}{c / μ}$
$t = \frac{10 \times 1 0 ^{- 2}}{2 \times 1 0 ^{8}}$
$(∴ \frac{c}{μ} = \frac{3 \times 1 0 ^{8}}{1.5} = 2 \times 1 0^{8} m s^{- 1})$
$t = 0.5 \times 1 0^{- 9} s$