Question

If the value of ${\cot }^{-1}\frac{3}{4}+{\sin }^{-1}\frac{5}{13}$ is ${\sin }^{-1}\left(\frac{a}{b}\right)$ then find $b-a$.

Answer 1

Answer: 2.00

${\tan }^{-1}\frac{4}{3}+{\tan }^{-1}\frac{5}{12}$
${\tan }^{-1}\left(\frac{48+15}{36-20}\right)$
${\sin }^{-1}\frac{63}{65}$