If the value of Avogadro number is 6.023 × 1023 mol -1 and the value of Boltzmann constant is 1.380 × 10-23 JK -1, then the number of significant digits in the calculated value of the universal gas constant is

Question

If the value of Avogadro number is 6.023 × 1023 mol -1 and the value of Boltzmann constant is 1.380 × 10-23 JK -1, then the number of significant digits in the calculated value of the universal gas constant is (A)  (B)  (C)  (D)

Tardigrade Admin · Accepted Answer

k =( R / N A ) R = kN A =1.380 × 10-23 × 6.023 × 1023 =8.31174 ≈ 8.312

Q. If the value of Avogadro number is $6.023 \times 1 0^{23} m o l^{- 1}$ and the value of Boltzmann constant is $1.380 \times 1 0^{- 23} J K^{- 1}$ , then the number of significant digits in the calculated value of the universal gas constant is

$k = \frac{R}{N _{A}}$
$R = k N_{A}$
$= 1.380 \times 1 0^{- 23} \times 6.023 \times 1 0^{23}$
$= 8.31174$
$\approx 8.312$

Q. If the value of Avogadro number is 6.023×1023mol−1 and the value of Boltzmann constant is 1.380×10−23JK−1, then the number of significant digits in the calculated value of the universal gas constant is

k=NA​R​ R=kNA​ =1.380×10−23×6.023×1023 =8.31174 ≈8.312

Q. If the value of Avogadro number is $6.023 \times 1 0^{23} m o l^{- 1}$ and the value of Boltzmann constant is $1.380 \times 1 0^{- 23} J K^{- 1}$ , then the number of significant digits in the calculated value of the universal gas constant is

$k = \frac{R}{N _{A}}$
$R = k N_{A}$
$= 1.380 \times 1 0^{- 23} \times 6.023 \times 1 0^{23}$
$= 8.31174$
$\approx 8.312$