Question

If the total kinetic energy of a rolling solid cylinder is 24 J then its rotational kinetic energy is

• A. 8 J
• B. 12 J
• C. 16 J
• D. 20 J

Answer 1

Answer: (A)

Total K.E. = $\frac{3}{4}m{V}^2=24$
Rotational K.E. = $\frac{m{V}^2}{4}=8J$