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Physics
If the total kinetic energy of a rolling solid cylinder is 24 J then its rotational kinetic energy is
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Q. If the total kinetic energy of a rolling solid cylinder is 24 J then its rotational kinetic energy is
A
8 J
B
12 J
C
16 J
D
20 J
Solution:
Total K.E. = $\frac{3}{4} mV^2 = 24$
Rotational K.E. = $\frac{mV^2}{4} = 8J$