If the total binding energies of 12 H , 24 He , 2656 Fe 92235 U nuclei are 2.22,28.3,492 and 1786 MeV respectively, identify the most stable nucleus of the following.

Question

If the total binding energies of 12 H , 24 He , 2656 Fe 92235 U nuclei are 2.22,28.3,492 and 1786 MeV respectively, identify the most stable nucleus of the following. (A)  2656 Fe (B)  12 H (C)  92235 U (D)  24 He

Tardigrade Admin · Accepted Answer

B.E H=(2.22/2)=1.11 B. E He =(28.3/4)=7.08 B. E Fe =(492/56)=8.78= operatornamemaximum B. E U =(1786/235)=7.6 2656 Fe is most stable as it has maximum binding energy per nucleon.

Q. If the total binding energies of $_{1}^{2} H,_{2}^{4} He,_{26}^{56} F e &_{92}^{235} U$ nuclei are $2.22, 28.3, 492$ and $1786 M e V$ respectively, identify the most stable nucleus of the following.

$_{26}^{56} F e$

$_{1}^{2} H$

$_{92}^{235} U$

$_{2}^{4} He$

B.E $_{H} = \frac{2.22}{2} = 1.11$
B. $E_{He} = \frac{28.3}{4} = 7.08$
B. $E_{F e} = \frac{492}{56} = 8.78 = maximum$
B. $E_{U} = \frac{1786}{235} = 7.6$
$_{26}^{56} F e$ is most stable as it has maximum binding energy per nucleon.

Q. If the total binding energies of 12​H,24​He,2656​Fe&92235​U nuclei are 2.22,28.3,492 and 1786MeV respectively, identify the most stable nucleus of the following.

2656​Fe

12​H

92235​U

24​He