If the time period of oscillation of a pendulum is measured as 2.5 second using a stop watch with the least count (1/2) second, then the permissible error in the measurement is

Question

If the time period of oscillation of a pendulum is measured as 2.5 second using a stop watch with the least count (1/2) second, then the permissible error in the measurement is (A) 10 % (B) 30 % (C) 15 % (D) 25 %

Tardigrade Admin · Accepted Answer

We have, (Δ t/t) =(0.5/2.5)=(1/5) (Δ t/t) % =(1/5) × 100=20 %

Q. If the time period of oscillation of a pendulum is measured as 2.5 second using a stop watch with the least count $\frac{1}{2}$ second, then the permissible error in the measurement is

10 %

30 %

15 %

25 %

20 %

We have, $\frac{Δ t}{t} = \frac{0.5}{2.5} = \frac{1}{5}$
$\frac{Δ t}{t} % = \frac{1}{5} \times 100 = 20%$

Q. If the time period of oscillation of a pendulum is measured as 2.5 second using a stop watch with the least count 21​ second, then the permissible error in the measurement is