If the time period of oscillation of a pendulum is measured as 2.5 second using a stop watch with the least count (1/2) second, then the permissible error in the measurement is %

Question

If the time period of oscillation of a pendulum is measured as 2.5 second using a stop watch with the least count (1/2) second, then the permissible error in the measurement is % (A)  (B)  (C)  (D)

Tardigrade Admin · Accepted Answer

We have, (Δ t/t) =(0.5/2.5)=(1/5) (Δ t/t) % =(1/5) × 100=20 %

Q. If the time period of oscillation of a pendulum is measured as 2.5 second using a stop watch with the least count $\frac{1}{2}$ second, then the permissible error in the measurement is ____ %

We have, $\frac{Δ t}{t} = \frac{0.5}{2.5} = \frac{1}{5}$
$\frac{Δ t}{t} % = \frac{1}{5} \times 100 = 20 %$

Q. If the time period of oscillation of a pendulum is measured as 2.5 second using a stop watch with the least count 21​ second, then the permissible error in the measurement is ____ %

We have, tΔt​=2.50.5​=51​ tΔt​%=51​×100=20%

Q. If the time period of oscillation of a pendulum is measured as 2.5 second using a stop watch with the least count $\frac{1}{2}$ second, then the permissible error in the measurement is ____ %

We have, $\frac{Δ t}{t} = \frac{0.5}{2.5} = \frac{1}{5}$
$\frac{Δ t}{t} % = \frac{1}{5} \times 100 = 20 %$