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Mathematics
If the tangent to the curve y=x3-x2+x at the point (a , b) is also tangent to the curve y=5 x2+2 x-25 at the point (2,-1), then |2 a+9 b| is equal to
Q. If the tangent to the curve
y
=
x
3
−
x
2
+
x
at the point (a , b) is also tangent to the curve
y
=
5
x
2
+
2
x
−
25
at the point
(
2
,
−
1
)
, then
∣2
a
+
9
b
∣
is equal to
2001
1
JEE Main
JEE Main 2022
Application of Derivatives
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Answer:
195
Solution:
y
=
5
x
2
+
2
x
−
25
P
(
2
,
−
1
)
y
′
=
10
x
+
2
y
P
′
=
22
∴
tangent to curve at
P
y
+
1
=
22
(
x
−
2
)
y
=
22
x
−
45
d
x
d
y
∣
∣
C
2
=
3
x
2
−
2
x
+
1
d
x
d
y
∣
∣
Q
=
3
a
2
−
2
a
+
1
Hence
3
a
2
−
2
a
+
1
=
22
∴
3
a
2
−
2
a
−
21
=
0
3
a
2
−
9
a
+
7
a
−
21
=
0
a
=
3
b
=
21∣2
a
+
9
b
∣
=
195
at
a
=
−
7/3
tangent will be parallel
Hence it is rejected