Tardigrade
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Tardigrade
Question
Mathematics
If the tangent at (1,1) on y2=x(2-x)2 meets the curve again at P then the co-ordinates of P are
Q. If the tangent at
(
1
,
1
)
on
y
2
=
x
(
2
−
x
)
2
meets the curve again at
P
then the co-ordinates of
P
are
90
130
Application of Derivatives
Report Error
A
(
4
9
,
8
3
)
B
(
3
,
3
)
C
(
4
,
4
)
D
none of these
Solution:
d
x
d
y
∣
∣
(
1
,
1
)
=
−
2
1
;
x
1
−
1
y
1
−
1
=
−
2
1
;
2
y
1
+
x
1
=
3
which is satisfying option (1)