If the system of equations, a2 x-a y=1-a b x+(3-2 b) y=3+a possess a unique solution x=1, y=1 then :

Question

If the system of equations, a2 x-a y=1-a b x+(3-2 b) y=3+a possess a unique solution x=1, y=1 then : (A) a=1 ; b=-1 (B) a =-1, b =1 (C) a =0, b =0 (D) none

Tardigrade Admin · Accepted Answer

put x=1 y=1 and solve for a b. In B C system has infinite solutions

Q. If the system of equations, $a^{2} x - a y = 1 - a & b x + (3 - 2 b) y = 3 + a$ possess a unique solution $x = 1$ , $y = 1$ then :

$a = 1; b = - 1$

$a = - 1, b = 1$

$a = 0, b = 0$

none

put $x = 1$ & $y = 1$ and solve for $a & b$ . In B \& C system has infinite solutions

Q. If the system of equations, a2x−ay=1−a&bx+(3−2b)y=3+a possess a unique solution x=1, y=1 then :

a=1;b=−1

a=−1,b=1

a=0,b=0