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Mathematics
If the system of equations, a2 x-a y=1-a b x+(3-2 b) y=3+a possess a unique solution x=1, y=1 then :
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Q. If the system of equations, $a^2 x-a y=1-a \& b x+(3-2 b) y=3+a$ possess a unique solution $x=1$, $y=1$ then :
Determinants
A
$a=1 ; b=-1$
B
$a =-1, b =1$
C
$a =0, b =0$
D
none
Solution:
put $x=1$ & $y=1$ and solve for $a \& b$. In B \& C system has infinite solutions