If the surfaces shown in figure are frictionless, the ratio of T1 and T2 is

Question

If the surfaces shown in figure are frictionless, the ratio of T1 and T2 is (A) √3: 2 (B) 1: √3 (C) 1: 5 (D) 5: 1

Tardigrade Admin · Accepted Answer

<img class="img-fluid question-image" alt="image" src="https://cdn.tardigrade.in/img/question/physics/68be152fb753bed2081074d51f06426f-.png" /> Acceleration of the system is a=(F/3+12+15)=(F/30)m s-2 ; T2=3a=3×(F/30)=(F/10) T1=(3+12)a=(3+12)×(F/30)=(F/2) ∴ (T1/T2)=(5/1)=5: 1

Q. If the surfaces shown in figure are frictionless, the ratio of $T_{1}$ and $T_{2}$ is

$3 : 2$

$1 : 3$

$1 : 5$

$5 : 1$

Acceleration of the system is
$a = \frac{F}{3 + 12 + 15} = \frac{F}{30} m s^{- 2}; T_{2} = 3 a = 3 \times \frac{F}{30} = \frac{F}{10}$
$T_{1} = (3 + 12) a = (3 + 12) \times \frac{F}{30} = \frac{F}{2}$
$∴ \frac{T _{1}}{T _{2}} = \frac{5}{1} = 5 : 1$

Q. If the surfaces shown in figure are frictionless, the ratio of T1​ and T2​ is

3​:2

1:3​

1:5

5:1