If the surface tension of water is 0.06 N m-1, then the capillary rise in a tube of a diameter 1 mm is (Take θ = 0°)

Question

If the surface tension of water is 0.06 N m-1, then the capillary rise in a tube of a diameter 1 mm is (Take θ = 0°) (A) 1.22 cm (B) 2.44 cm (C) 3.12 cm (D) 3.86 cm

Tardigrade Admin · Accepted Answer

As h = ( 2S cos θ/r ρ g) = ( 2 × 0.06 × cos 0°/0.5 × 10-3 × 103 × 9.8) = 2.44 × 10-2 m = 2.44 cm

Q. If the surface tension of water is $0.06 N m^{- 1}$ , then the capillary rise in a tube of a diameter 1 mm is (Take $θ$ = 0°)

1.22 cm

2.44 cm

3.12 cm

3.86 cm

As $h = \frac{2 S c o s θ}{r ρ g}$
= $\frac{2 \times 0.06 \times c o s 0 ^{\circ}}{0.5 \times 1 0 ^{- 3} \times 1 0 ^{3} \times 9.8}$
= $2.44 \times 1 0^{- 2} m = 2.44 c m$

Q. If the surface tension of water is 0.06Nm−1, then the capillary rise in a tube of a diameter 1 mm is (Take θ = 0°)