Question

If the sum of the roots of the equation $(m+1)x^2+2mx+3=0$ is $1$, then the value of $m$ is

• A. $\frac{1}{2}$
• B. $-\frac{1}{2}$
• C. $\frac{1}{3}$
• D. $-\frac{1}{3}$

Answer 1

Answer: (D)

Sum of the roots = $-\frac{2m}{m+1}=1$
$\Rightarrow -2m=m+1$
$\Rightarrow -3m=1$
$\Rightarrow m=-\frac{1}{3}$.