If the string all the pulleys are ideal, acceleration of mass m is

Question

If the string all the pulleys are ideal, acceleration of mass m is (A) ( g /2) (B) 0 (C) g (D) dependent on m

Tardigrade Admin · Accepted Answer

<img class="img-fluid question-image" alt="image" src="https://cdn.tardigrade.in/img/question/physics/1008365486e66df61e84f1af791bc8dc-.png" /> As net force on a massless object is always zero. for the pulley D, equating the forces, g the forces, 2T = T ∴ T=0 mg - T = ma ∴ am=g downarrow

Q. If the string & all the pulleys are ideal, acceleration of mass $m$ is

$\frac{g}{2}$

$0$

$g$

dependent on $m$

As net force on a massless object is always zero.
for the pulley $D$ ,
equating the forces,
g the forces,
$2 T = T$
$∴ T = 0$
$m g - T = ma$
$∴ a_{m} = g ↓$

Q. If the string & all the pulleys are ideal, acceleration of mass m is

2g​

0

g

dependent on m

As net force on a massless object is always zero. for the pulley D, equating the forces, g the forces, 2T=T ∴T=0 mg−T=ma ∴am​=g↓

Q. If the string & all the pulleys are ideal, acceleration of mass $m$ is

$\frac{g}{2}$

$0$

$g$

dependent on $m$

As net force on a massless object is always zero.
for the pulley $D$ ,
equating the forces,
g the forces,
$2 T = T$
$∴ T = 0$
$m g - T = ma$
$∴ a_{m} = g ↓$