If the standard molar enthalpy change for combustion of graphite powder is -2.48 × 102 kJ mol -1, the amount of heat generated on combustion of 1 g. of graphite powder is k J.

Question

If the standard molar enthalpy change for combustion of graphite powder is -2.48 × 102 kJ mol -1, the amount of heat generated on combustion of 1 g. of graphite powder is k J. (A)  (B)  (C)  (D)

Tardigrade Admin · Accepted Answer

1 mol graphite =12 gm C Ans. =(248/12)=20.67 kJ / gm heat evolved

Q. If the standard molar enthalpy change for combustion of graphite powder is $- 2.48 \times 1 0^{2} k J m o l^{- 1}$ , the amount of heat generated on combustion of $1 g$ . of graphite powder is _________ $k J$ .

$1 m o l$ graphite $= 12 g m C$
Ans. $= \frac{248}{12} = 20.67 k J / g m$ heat evolved

Q. If the standard molar enthalpy change for combustion of graphite powder is −2.48×102kJmol−1, the amount of heat generated on combustion of 1g. of graphite powder is _________kJ.

1mol graphite =12gmC Ans. =12248​=20.67kJ/gm heat evolved

Q. If the standard molar enthalpy change for combustion of graphite powder is $- 2.48 \times 1 0^{2} k J m o l^{- 1}$ , the amount of heat generated on combustion of $1 g$ . of graphite powder is _________ $k J$ .

$1 m o l$ graphite $= 12 g m C$
Ans. $= \frac{248}{12} = 20.67 k J / g m$ heat evolved