Question

If the standard electrode potential of $C{u}^{2+}/Cu$ electrode is $0.34V$, what is the electrode potential of $0.01M$ concentration of $C{u}^{2+}?(T=298K)$

• A. 0.399 V
• B. 0.281 V
• C. 0.222 V
• D. 0176 V

Answer 1

Answer: (B)

$C{u}^{2+}+2e^{-}\to Cu$
At $298K$
$E=E^0-\frac{0.0591}{n}log\frac{1}{[M^{n+}]}$
$E_{{Cu}^{2+}/Cu}-\frac{0.0591}{2}log\frac{1}{10^2}$
$=(0.34-0.0591)V$
$=0.2809V$