If the standard deviation of 3, 8, 6, 10, 12, 9, 11, 10, 12, 7 is 2.71, then the standard deviation of 30, 80, 60, 100, 120, 90, 110, 100, 120, 70 is

Question

If the standard deviation of 3, 8, 6, 10, 12, 9, 11, 10, 12, 7 is 2.71, then the standard deviation of 30, 80, 60, 100, 120, 90, 110, 100, 120, 70 is (A) 2.71 (B) 27.1 (C) (2.71)√10 (D) (2.71)√2

Tardigrade Admin · Accepted Answer

We know that, the standard deviation is dependent on scale. If the values in the sample are multiplied by

k

, then the standard deviation will be multiplied by

k

.
So, in given series/sample, multiplied by 10 , then the resulting standard deviation is

= 10 \times 2.71 = 27.1

Q. If the standard deviation of $3$ , $8$ , $6$ , $10$ , $12$ , $9$ , $11$ , $10$ , $12$ , $7$ is $2.71$ , then the standard deviation of $30$ , $80$ , $60$ , $100$ , $120$ , $90$ , $110$ , $100$ , $120$ , $70$ is

$2.71$

$27.1$

$(2.71) 10$

$(2.71) 2$

$0.271$

We know that, the standard deviation is dependent on scale. If the values in the sample are multiplied by $k$ , then the standard deviation will be multiplied by $k$ .
So, in given series/sample, multiplied by 10 , then the resulting standard deviation is
$= 10 \times 2.71 = 27.1$

Q. If the standard deviation of 3, 8, 6, 10, 12, 9, 11, 10, 12, 7 is 2.71, then the standard deviation of 30, 80, 60, 100, 120, 90, 110, 100, 120, 70 is

2.71

27.1

(2.71)10​

(2.71)2​

0.271

We know that, the standard deviation is dependent on scale. If the values in the sample are multiplied by k, then the standard deviation will be multiplied by k. So, in given series/sample, multiplied by 10 , then the resulting standard deviation is =10×2.71=27.1